P Y S C R I P T E R.

We had c, s, r.

Let's multiply s times r.

P R I A M O S. This morning?

R. M. Aller de S. de Compostela

You get s times 1 minus r all I did is I factored out the s is equal to r to the first power minus r to the n plus 1.

P of H given R comma S times P of R plus P of H given not R and S times P of not R, which is total probability.

P of happiness given S and R times P of S and R, which is of course the product of those 2 because they are independent, plus P of happiness given not S R, probability of not as R plus P of H given S and not R times the probability of P of S and not R plus the last case,

So now we have q , r , and s .

This is a Bayes network of which S and R are independent but H adds a dependence between S and R.

This is the same as probability of R, and R and S are independent.

Obviously, it isn't because if I now vary S from S to not S, it affects my probability for the variable R.

Using Bayes' rule, you can transform this into P of H given R comma S times P of R given S over P of H given S.

P of H given not S and not R.

O, P, Q, R, S, T there you go.

However, if I know something about the variable H, then S and R become dependent that is, knowing about my happiness over here renders S and R dependent.

It's little discrete that's spelled D I S C R E T E bits.

Not all of them are divisible by either r or s.

So r times s is going to be equal to what?

That is a really unusual situation where we have R and S are independent but given the variable H, R and S are not independent anymore.

We observe the conditional independence of R and S to simplify this to just P of R, and the denominator is expanded by folding in R and not R,

For the maximization, we can safely draw up gamma and R(s).

We have to get the s, take the s off the list and check all the neighbors of s, u, r, p, and q.

Suppose we wanted to compute the probability of C given s and r.

I. P. R

R ...? R ...

This is equal to L to the... ...L to the r over s power

I like R B.

This is only divisible by r, that's only divisible by s, that's divisible by neither.

kdesu c d f file i icon name n p priority r s t u user nonewdcop command arg1 arg2

R, mom. Mom, r.

Can i call you r?

Get some R and R?

I only have 1's, 10's, and 100's and 1,000's bills and so forth.

The really interesting thing is that in the absence of information about H, which is the middle case over here, the probability of R is unaffected by knowledge of S that is, R and S are independent.

S....s...

So I've added two more checkboxes type checkbox and I've made their names be r and s .

r

r

R

r

R

R

R

G E R A R D.