There are max nodes, min nodes, and chance nodes.

All the purple nodes are connected to other purple nodes but not to the nonpurple nodes, and in fact, you can see that the nonpurple nodes can all speak to each other.

Nodes

All the nodes are numbered less than n.

Move Nodes

Delete Nodes

Delete nodes

DHT Nodes

Total Nodes

Free Nodes

Minor Nodes

There there are maximizing nodes and minimizing nodes.

It's not actually that the product of the nodes times the nodes times the nodes.

That can use two nodes That can use two nodes. That can use two nodes

We've satisfied variant number one, we've colored all the nodes.

For the chance nodes, all the possibilities are equally probably.

These are all of the nodes that connect to this.

But when we care about the height of the red black tree, of course, we care about all of the nodes, the red nodes and the black nodes.

C can reach all of these nodes and through one of those nodes one tree edge gets it to one.

In particular, suppose we color all three of the nodes, black.

So we've now post ordered all the nodes in the graph.

What matters is which nodes are connected to which other nodes.

We'll repeat this for all the nodes, all the edges, and then we're basically done.

Now let's consider the degree of all the nodes in the graph.

Here is a graph with 5 nodes and the degree of all of the nodes is even 2, 4, 2, 4, and 2.

This node is connected to all the other nodes. This one is done.

But what if instead of having these be terminal nodes, these were cutoff nodes, and these were evaluation values for those nodes?

Some nodes have no children.

Nodes here being computers, right?

Gone to your lymph nodes.

Some of those nodes will be black some of those nodes will be red.

It says, well actually, black nodes are a majority of nodes in the tree.

For each node, we check all of its neighbors and once you add that up over all possible nodes whether all the neighbors of all the nodes, that's (M), so it's constant work for each of those edges.

If these are max nodes, we've skipped the opponent's moves, which are the min nodes.

We're assuming that there are n nodes and the nodes are arranged in a square.

So we take on a list of nodes. We'll use 6 nodes in this example.

That can use two nodes. Now there's just no pathway that can use two nodes

Automatically expand nodes in tree mode

Here's a hypercube on eight nodes.

We'll call them A and B, where A has three nodes and B has five nodes.

Now what we're going to do is choose half of the nodes from G1 and half of the nodes that are in G2, and connect all pairs.

And then for each of those nodes what we do is we sum up for all the pairs of nodes that are neighbors of the node v.

Women used to get really debilitating surgeries to excise all of the axillary lymph nodes.

So, all paths still have equal number of black nodes and invariant four remains satisfied.

There's all sorts of relationships that you can figure out between nodes and their parents.