Approximately.

And so, that is so y would be approximately equal to the plus or minus.

And so it would be sort of approximately up there, coming out of the animal kingdom.

So y would be approximately equal to positive or negative x over 2, or 1 2x.

It's better to be approximately right than completely wrong.

Approximately two weeks.

This is approximately ...

Approximately 80 say

is approximately 3,720to1.

And they look as follows approximately 0.1698 and approximately 0.8301.

What's this city's population, approximately?

These are all 0.2s approximately.

This one took me approximately,

As before, without it'd be 1, but with it'd be 2 3 or approximately 0.667.

When you run this 1,000 times, your output should be approximately 2 3.

So we could say, hey, Maple is approximately Old River, or M is approximately River plus 1,000.

The trip will take approximately five hours.

The bridge is approximately a mile long.

The total is approximately ten thousand dollars.

Same for this guy, it's approximately 0.091.

The price has stayed approximately the same.

That one took me approximately six weeks.

We could say approximately equals, or whatever.

Chuck in approximately 30 seconds, fired 16 times.

I used the telescope approximately 1 mil dot

Since then, the world has used approximately half.

It should pass Marshfield in approximately 78 minutes.

The square root of 2 is approximately 1.414.

The square root of 20 is approximately 4.472.

You say he's been missing approximately four weeks?

We have estimated the damages to approximately 4,5 million.

My foot is covering approximately 300 miles of mycelium.

Field upgrade is approximately zero. It's not actually zero.

There are approximately 3,500 ivory beads in this burial.

This just means not exactly but approximately equal to.

This would be 0, this would be minus 2x.

This would be 7 and this would be 3.

And maybe that would be, that would be what?

Light would be dragged down the hole as everything else would be, and all that would be left would be a shadow.

On the graph of f(x) x² this would be 4, this would be 2, this would be 1, this would be 3.

You already calculated this one before, which is approximately 0.043, and this one over here is 1 minus that, which is 0.957 approximately.

If I now run this, I get for my x vector approximately 16 the number over here, approximately 8 the number over here.

Is the relationship between age and wage exactly linear, approximately linear, or there seems to be no relationship?

Would our world be different? Would we be further behind?

What would I be? What would I be?