And then the numerator is the factorial of my exponent.

And you can put a t n here and use an inductive argument to figure out a general formula.

In general, young people dislike formality.

In this video I want to do a couple of inequality problems that are deceptively tricky.

So I'll just re write that as c.

We could start setting the boundaries, but let's just keep the region abstract.

And you know, the actual letters I chose don't matter.

That makes sense, because the separable differential equations are really just implicit derivatives backwards.

So you get y minus b plus k over 2 is equal to 1 over 2 times b minus k, times x minus a squared.

That's equal to that.

So let's see if we can use this with this information to get a generalized formula.

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And that's where that plus c comes from.

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Or I could write one to five.

OK, so I already have a guess of why this won't have a solution.

Now, the interesting thing to do is let's say I have a parabola.

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