I want positions and tactical status immediately.

Fast enough to get to that tank before it got to Kyle's position.

Let me put the Laplace transform of and I'm also going to the sides.

He's still programmed with our tactics and base locations?

That's the vector in standard position.

Now let's look at a path through this state.

So let's just start at some arbitrary point.

Maximum effective range is one thousand meters.

Initially, the monkey is at location A. The bananas are at location B.

From the camera's point of view, if we subtracted 5 from all the world coordinates, everything would be nicely oriented for the camera.

Initially this robot has no clue where it is. It faces what we call a global localization problem.

So, now that we can do things with my robot.

We're in position.

Standing by.

I'm in position.

He's in position now?

We can do the same thing with lists.

Here you have overhead motion capture cameras on the top that tell the robot where it is 100 times a second.

Let me give you those for our example of the one demotion of an object

So now we know the bug is triggered or the problem lies in 1 of these 3 lines.

We just put a tighter rubber band between them. It's not 2 anymore it's now 1.

So on the next string, the new string, that position is going to be an x.

Three times nine is equal to twenty seven.

It's got the (E E).

But if we were to draw it in standard form remember, in standard form b minus a would look something like this.

Now I'm going to say that these are position vectors, that we draw them in standard form.

As you see the 7, we're willing to go to 5.1, but not quite all the way because we feel fairly confident on our wrong prior estimate.

And so we want to print that out as we were doing before.

We replace that with the replacement, and finally we want to concatenate the part of the string after the match.

No fuel is burnt.

He won't show me location number 2, because that's the one I guessed.

(Audience B.) Nicholas Christakis B, it's obvious.

We took a good place to see the parade.

Then what I might get out looks as follows there's 3 landmarks.

I just can't do it.

So here 10 and 11 are misplaced because they should be there and there, respectively, 12 is in the right place, 13 is in the right place, and 14 and 15 are misplaced.

American forces are still in position.

American force are still in position.

I'll be right there. Action stations, action stations.

We'll be given coordinants x and y, and the object we're tracking moves in 2 dimensional space, and we wish to use a Kalman filter to understand where the object is, what its velocity is, and even be able to predict a future location based on the estimate of the position and its velocity.

If so, we increment the position and sort of bump it one space to the right in the sorted list.

Suppose you place the largest disk first, which has three different locations.

In this mode, he's trying to maintain his position.

I've made a couple of helpful routines to help with the heap. given a position i in the heap, left (i) returns the position of the left child.

It's not enough to generally just say oh. There's some cat stuff here.