Or another way of writing that is v1 dot v1.

(Laughter)

Well that's equal to 1.

So you're going to get some combination of the i and j unit vectors.

Transform of any arbitrary function very, very quickly.

There, we just set up a equation with one unknown and we can solve for x.

So that's where you get the intuition that it's x minus 2y times x minus 2y.

So, you still think space objects are trying to kill you even after what I've told you so far?

We're multiplying our f of t times e to the 1t.

You take a vector, you dot it with itself, and you get the

If you distribute the negative 3, you're going to get that expression.

Got it.

We have a lot of interesting information about what complexity is.

In 2004, if we assume the pattern continues, let's add another 75.

And in three minutes, we filled in another table in our

So we throw away our old pi, pi1, and replace it with a new pi, pi2 which is a result of solving the MDP described by our new estimates of the utiliities.

So, minus 2 3 x, you go down 2 for every 3 that you go out.

We'd also want to multiply the right hand side by x.

You multiply that times negative 8

Someone has to say, well, when x is 2, y is 3.

Boring. It's just not interesting neurally.

And you probably know, hey, well, if I take 2 away from 5,

4 and negative 21 look tantalizing, but when you add them, you get negative 17.

They say, you have found more than one solution that satisfies the system.

And then you'd get x could be equal to negative 8, or x could be equal to negative 10.

Plus 1 s that's this right there times the Laplace transform of 1.

So this is our dr right here.

And so, if we just put this on the other side of the equation, what do we get?

Do we have 20,000? Yes, we have 20,000!

And if you'd give me some other point right here, I'll relate it to another member of y.

You've earned it.

And then we can essentially just add and subtract them from the center.

We have AC and DC, get 12 volts DC, so that could be used for certain applications.

So I get x squared plus b a x is equal to you have to divide both sides by a minus c a.

And then we distribute again.

We have a surplus to sell in the market.

And now I evaluate this at 1 and 0.

let's just divide by a again.

So this was c plud d i, so this is its conjugate.

We multiply the denominators 3 times 2 is 6.

Is that satisfactory, Mr. Barris?

This means that, once you have one infinity, you can always make a bigger one by making the set of all subsets of that first set.

We got rid of the stuff that didn't.

So then, each time the big fish eats the little fish, he will increment the score, and the score will go up by one.

And of course, the 1's cancel out and we got the 3 times 2.