You need one variable and a value or variable to do a ' '

But we can add clean water.

That's the exact same this is just the exact same way of writing the exact same thing.

I have extended the test function a bit, such that there would be a test counter up here.

We have 2 types of NUMs.

And what I mean is... to be clear, in order to be divisible by 15 it has to have at least one 3 and at least one 5 in its prime factorization, so it needs to have one 3 and at least one 5.

And so the other question that might be popping in your brain is, Sal, when we did first order differential equations, we only had one constant.

So just if you were actually to count objects, and you have at least one of them, we're talking about the natural numbers.

Let's first look at how we can create the pattern from the pattern number.

Let's see, they are three apart.

At least one resource agent has been found.

To do that, we're going to learn two really big ideas in computer science.

10 and 12.

Import macros that are contained in one or more files.

So R2 is the set of all lists of real numbers, and let me make one of the lists.

Here's our plan of action for solving this problem.

I'll draw them in rows of three.

Ben So 3 is a factor

Math is just another language.

But remember, part of our definition, it needs to be divisible by exactly two natural numbers.

So it is not prime, technically, because it only has 1 as a factor it does not have two factors.

There are other ways to get at this, but I feel this is the most intuitive.

So let's clean this up a little bit so we remember what we did.

So again, to recap where we got to on the previous slide.

So there are 3 cases.

Then you count the decimal spots. one, two.

So what's the most number of prime factors that they have in common?

What we need to make sure is that there aren't too many steps.

We have a close parenthesis followed by 1956 followed by an open parenthesis.

So what's the profit going to be? So let me write this down.

We want to know how far does the column move?

But realize had there been one fewer 9, there would have been other candidates for the mode as well.

So every time you multiply something by 10, you're shifting the decimal over to the right once.

First we extract the size of the grid by looking simply at the length of the list p.

1 1 is the only common factor

This format is not perfect yet.

Then we have the 7. Let me do that in another color.

Let, let's do some actual problems using functions.

So to avoid that, I want to put all of these I want to rewrite all of these as fractions.

Let me make a final quiz in which I have a coin which probability I don't know.

They also have problems with degenerate conditions.

Let's try that.

It's only divisible by 1 and 2.

And so when we're adding a positive and a negative, you're really finding the difference between the two.

Thegapdecreased to one point.