So where's the inverter?

AC

AC Adapter

I'm making an inverter named after him.

So in the numerator, we get a c I don't want to run out of space, I always do a c, so a times c, minus a d i, minus a d i these i's are looking funny this is an i.

We have this term, a times c, that's real.

You can only invent stories, not an inverter

When AC Adaptor is plugged in

C

So let's see what the real parts are.

That equals let's see, the real parts.

What is the length of the base

And then we distribute again.

So we can rewrite here.

And here is Gauss' trick, for observation, which is that the result of the third recursive call minus each of the first two what happens.

Let me rewrite it down here so we have it to work with.

It is 2 times the area of ABC, right over there

Never mind the design. I'll make the inverter and show you

Alternate interior angles

AC adaptor plugged in

AC adaptor unplugged

AB minus AE is the same thing based on these last few things that we saw

In the accompanying diagram, the measure of angle a is 32 degrees.

And we can get rid of d i.

I'll color code it

But then we can separate them out and we could say well, that equals a c plus b d over c squared plus d squared.

Let's say given this diagram right over here

We have AC and DC, get 12 volts DC, so that could be used for certain applications.

Which means that until then, I had worked on battery power.

Now let's remind ourselves what these two vectors were. v1 was the vector ac and v2 is the vector bd.

So, this must be parallel to that

Or we can say BE is the same thing as times BD

The way the unit works is, when the sun comes out, the engine will start and you get power out here.

Codecs to play mp3, sid, mpeg1, mpeg2, AC 3, DVD (without encryption)

So, this is parallel to that

So, first of all we view this as a transversal

And we've done our proof

All I said is, look if I have a times b plus c, this is the same things as ab plus ac.

So, to be more specific, our first 2 recursive calls are shared with the previous recursive algorithm. You go ahead and compute AC and BD recursively.

Ray AB starts at A or has a vertex at A and lets say that there is also a ray AC.

Then you see where this is going 2 times is , times AC times BD

We've showed that, look, diagonal DB is splitting AC into two segments of equal length and vice versa

And it turned out that it was this difference that caused the program to fail.

Quadrilateral ABCD they're telling us it is a rhombus

We know that this diagonal line over here is a perpendicular bisector so the height is just the distance from BE