I understand that but but if you think about epoxy, what's epoxy?

2 Real Part

Imaginary part is 2

End of Part 2

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It has a real part 2.

And I call it an epoxy method because it's not very appetizing.

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Then that means that the a 2 part is 25 right over here. Then that means that the b 2 part.

And on day two, we put those two pieces together. That's the epoxy.

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It has an imaginary part of 2 times i.

And then our imaginary part is a positive 2.

You take the imaginary part, minus 2i, minus 2, right?

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And of course, 4 times 2, that part over there,

Is a1 space 2 part of the possible return value?

So let's first think about the whole number part, the 2.

And you can see just what a shoestring operation this really was, because we cast these 16 blue LEDs in epoxy and you can see in the epoxy mold that we used, the word Ziploc is still visible.

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So, I'll see you in the part 2 of using the quadratic equation.

Whatever part of the circle we're in when y is equal to 2.

So in in this example, this complex number, our real part is 2.

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So this green triangle, this is part of the plane z is equal to 2.

Well, it's 2 2 2 2 2 gnus.

Well 5 2 is the same thing as 2 2 2 2 2.

2, 2 gnus, 2 gnus.

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I am going to rewirte this part as x to simplify we have 2 3 x 9.

So this part right over here is going to simplify to times 10 to the negative 2.

Now, in order to examine the run time, the key part here are these 2 for loops.

Well, you have 2 plus 2 plus 2 plus 2 plus 2.

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Well that means 2 times 2 times 2 times 2.

Here's another kind of prefiguring of epoxy because we've got glutenin and gliadin, neither of which are strong enough to make a good bread.

There are 2 parts to this problem, the first part is saving the vertex in the geometry object.

So 2 minus 2 times x1, so minus 2 times 2.

2 plus 2 plus 2 plus 2 is equal to 8.

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Next part. Let's do the next part.