And with cross multiplying, you're actually doing 2 steps.

This is multiplying by 10, this is multiplying it by 100.

Multiplying these with their normalizer gives us approximately 0.0089 and 0.991.

He should be multiplying.

So we're multiplying by 1.1.

We're multiplying the i components.

I'm multiplying it by 10.

We're multiplying it times B.

Multiplying something with A b modifies the mean in a very straightforward way.

Whatever is multiplying by nine. Whatever is multiplying by ninety nine is divisible by nine.

And you say, look, I'm not multiplying by ten. I'm not multiplying by a hundred.

And notice we're getting the exact same value that we got with cross multiplying.

I'm just multiplying this times itself.

We're essentially multiplying it by 100.

So we're essentially multiplying by 4.

So this 4 now we're multiplying.

We're multiplying the denominator times 9.

So this is multiplying by 2.

We're multiplying it by 10, twice.

Or you're multiplying it by 100.

We're essentially just multiplying by 1.

So right here we're not really multiplying seven times four, we're actually multiplying seven times forty.

I'm just multiplying the numerator and then multiplying the denominators 3x plus 2 times x minus 5.

This will print out the result of multiplying 52 3 and adding that to multiplying 12 9.

I just switched the order in which I'm multiplying, which you can do with multiplication.

We'll start with a special case of that, of matrix vector multiplication multiplying a matrix together with a vector.

Very quickly multiplying this guy with this girl over here 0.09. This guy with this girl over here 0.45.

You're multiplying the one by zero once.

Welcome to the presentation on multiplying expressions.

We're multiplying both sides by a positive.

And multiplying by the inverse of N.

And this is just multiplying a binomial.

I'm just multiplying that times a squared.

Multiplying these 2 things gives us 0.624.

There's an implicit 1 multiplying times this b.

We're multiplying it by 100 in the denominator.

And we're multiplying the two times each other.

So when we're multiplying times the entire expression

I'm just multiplying four times a minus fifteen.

Because you're multiplying the sum of these guys.

So we're multiplying this times one over b.

We're not multiplying the vectors times each other.

I can rewrite this by multiplying things out.

Well, what did we learn about multiplying matrices?

So we're multiplying by 10 8 over here.